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CIE 9709, A Level, Paper 32, October/November 2014 – Pure Mathematics 3 Answers

25 thoughts on “CIE 9709, A Level, Paper 32, October/November 2014 – Pure Mathematics 3 Answers

  • October 30, 2014 at 6:19 am
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    I just love your work. How are you so genius?
    Guide me with some tips.
    Upload 9709_w14_ms_12 as well.

    Thank you.

    Reply
      • October 30, 2014 at 4:55 pm
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        Oh, thanks a lot mate.

        Reply
    • November 4, 2014 at 9:48 pm
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      What do you reckon would be a minimum A this year
      Would it be 47 like last two years
      Or 51 above

      Reply
  • October 30, 2014 at 8:26 am
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    thanx a lot. how r u so intelligent?

    Reply
    • October 30, 2014 at 8:40 am
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      thank you also for the question paper. I hope I didn’t do any mistakes 🙂

      Reply
  • October 31, 2014 at 2:52 pm
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    You can post whatever answers after all the exams ! right now there is still examinations going on and if someone has gone throughout a bad exams these post may affect him and prevent him from doing well in other exams if he saw that the answers he got was not the same as yours !!!

    Reply
  • Pingback: Copyright … 9709_w14_ms_32 | JustPastPapers.com

  • November 5, 2014 at 1:58 pm
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    why are there not biology solutions in ur website

    Reply
    • November 5, 2014 at 2:56 pm
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      because we couldn’t find people to do them for free 🙂 But we have someone now that started working on them

      Reply
      • November 8, 2014 at 3:44 pm
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        Please upload mark schemes for October/November A2 Biology a lot of people need it!!
        Specially papers 42 & 52
        Thanks..

        Reply
  • November 26, 2014 at 8:26 pm
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    can i please have the short link to 9700, 9701 and 9702 oct/nov 2014 papers please??

    Reply
  • April 8, 2015 at 7:06 am
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    For 9709, A LEVEL, PAPER 32, OCTOBER/NOVEMBER 2014, the answer Q 6 ii, why do you start a0 = 2 ? Thanks

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    • August 19, 2015 at 6:06 pm
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      a>0; 1+ln2/a >1; a=0.5 *exp(1+ln2/a) ~= 0.5*3 and I took a=2 🙂
      e=2.7182818284 ~= 3

      Reply
  • May 16, 2015 at 8:16 am
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    Thanks for all your hard work. According to the mark scheme, Q8(III) has 3 answers, which is legit since it is X^3. I have no idea where the 3rd root come from, mind to take a look at it?

    Again, thanks. 🙂

    Reply
    • May 16, 2015 at 1:25 pm
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      from the 3rd step.. the one that i didn’t initially calculated (3theta = -sin^-1(3/4)+pi +/- 2pi) that gives x=2/root3 * sin([-sin^-1(3/4)+pi – 2pi]/3)= -1.121353855…

      Reply
  • August 18, 2015 at 5:20 pm
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    Oct/Nov 14 (9709) variant 33 solved?

    Reply
    • August 18, 2015 at 7:23 pm
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      we will scan it r just take pictures and will be up soon

      Reply
  • August 18, 2015 at 7:41 pm
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    Will it be up today?, because i have to submit my paper tomorrow, so if it is possible please upload it today.

    Thanks 🙂

    Reply
  • August 18, 2015 at 11:22 pm
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    Please guys variant 33 (9709), i would really appreciate it

    Reply

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